Pls ans it fast.

Pls ans it fast. The cyclic integral of the quantity (dq + dw) must be o Positive O Negative O Zero O Can't be inferred.

Dear Student ,

 From first law of thermodynamics, 
dQ + dW = dU                 (Note the I have taken the work done by the surrounding which is negative of the work done by the system, dQ                                           is heat supplied to the system dU is the change in the internal energy of the system.)
dU is a point function  
so it's integral over a cyclical path always be zero as you will reach the same point that you started with.
so ΔU = Zero 
Therefore the cyclical integral of dQ + dW will be zero.

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