Pls answer q17

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Please find below the solution to the asked query:

xcosα = ysinα + 1 \Rightarrow xcosα - ysinα - 1 = 0 Slope = m = - \frac{Coefficient of x}{Coefficient of y} = - \frac{cosα}{- sinα} = cotα 3 x^{2} - 4 xy + y^{2} = 0 \Rightarrow 3 x^{2} - 3 xy - xy + y^{2} = 0 \Rightarrow 3 x (x - y) - y (x - y) = 0 \Rightarrow x - y = 0 or 3 x - y = 0 If slope are m_{1} and m_{2}, then m_{1} = 1 and m_{2} = 3 Line will be parallel to xcosα = ysinα + 1 oif slopes are equal, hence m_{1} = m or m_{2} = m \Rightarrow 1 = cotα or 3 = cotα \Rightarrow \frac{1}{tanα} = 1 or \frac{1}{tanα} = 3 \Rightarrow tanα = 1 or tanα = \frac{1}{3}

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