Dear student (A) The given function is f(x)=x13 on -1,1The domain of f is given to be -1,1Differentiating f(x) with respect to x, we getf'x=13x-2/3We observe that at x=0,f'(x) is not defined Hence, Rolle's theorem is not applicable for the given function (D) The given function is f(x)=x+1x on 12,3The domain of f is given to be 12,3Differentiating f(x) with respect to x, we getf'(x)=1-1x2We observe that at x=1 f'(x) is not definedHence, Rolle's theorem is not applicable for the given functionSimilarly try for other parts Regards

Pls answer q26

Pls answer q26 24. least, is 25. 26. Iff - 27. (C) x-2r The value of a for which the sum of e squares of the roots of the equation — (a — 2) x — a I — O is 2 (B) Two towns A and B are 60 km apart. A school is to be built to serve 150 students in town A and 50 students in town B. If the total distance to be travelled by all 200 students is to be as small as possible, then the school should be built at : (A) town B (B) 45 km from town A -cer-—town A (D) 45 km from town B For which of the following functions is Rolle's Theorem not applicable? (A) (B) (C) (D) (C) f(x) x' g on I— 1, I J _f(x) tan—I x on to, 11 — on 11/2, 31 , (c) _ where f (x) — ex, a O and then : c loge (e— l) (B) logc l) loge —

Dear student

(A) The given function is f (x) = x^{\frac{1}{3}} on [- 1, 1] The domain of f is given to be [- 1, 1] Differentiating f (x) with respect to x, we get f' (x) = \frac{1}{3} x^{- 2 / 3} We observe that at x = 0, f' (x) is not defined . Hence, Rolle' s theorem is not applicable for the given function . (D) The given function is f (x) = x + \frac{1}{x} on [\frac{1}{2}, 3] The domain of f is given to be [\frac{1}{2}, 3] Differentiating f (x) with respect to x, we get f' (x) = 1 - \frac{1}{x^{2}} We observe that at x = 1 . f' (x) is not defined Hence, Rolle' s theorem is not applicable for the given function Similarly try for other parts .

Regards

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