Pls answer this question from wave optics Share with your friends Share 0 Rohit Babu answered this Dear Student,Given,λ=5460A0=5460×10-10m, d=0.1mm=0.1×10-3m, D=20cm=0.2mLet θ be the angular position of nth dark fringe.We have,dsinθ=2n-1λ2For first dark fringe, n=1⇒dsinθ=2×1-1λ2=λ2⇒sinθ=λ2d=5460×10-102×0.1×10-3=2.73×10-3⇒θ=sin-12.73×10-3=0.1564≈0.160 ,Option 2Regards. 1 View Full Answer @#@#@#@#@# 🔛 answered this Shrutika. ....... 1 @#@#@#@#@# 🔛 answered this Hello.... 1
