# Pls answer this question sir..

**Dear student,**

We know diagonals of rectangle bisect each other .So

**Step 1-**Draw a line As : AO = $\frac{6}{2}$ = 3 cm

**Step 2 -**Now draw a angle of 45$\xb0$ at point O , and cut arc of 3 cm and mark that point is B , So we have $\angle $ AOB = 45$\xb0$ .

**Step 3 -**Now we extend our line segment AO to AC as take arc of OC = 3 cm , and OB to BD , as OD = 3 cm

**Step 4 -**Now join Point A , B , C and D

Hence we obtain ABCD as a rectangle .

**Regards**

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