Pls answer this question....

Here, formula used is

\lim_{x \to 0} \frac{a^{x} - 1}{x} = \log a

So,

\lim_{x \to 0} \frac{b^{x} - 1}{x} = \log b a n d \lim_{x \to 0} \frac{{(a + b)}^{x} - 1}{x} = \log (a + b)

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