Pls answer this question


Dear Student

The work done against gravity can be calculated from the increases in height of the centre of mass.

The centre of mass of a worm folded in two is located at the middle of either half, i.e., at a point one-quarter of the worm's total length from one end, as given in the figure.
solution
Thus, the centre of mass of the narrow flat worm travels 5cm up the wall becuase its centre of mass is lies at 5cm.
So distance covered by centre of mass to cover whole wall is 10-5 = 5 cm
Work done = mgh = 5mg
Now other worm moves 7.5cm on wall becuase its centre of mass lies 2,5 cm from each end.
Hence distance travelled by worm's centre of mass to reach to top is 10 - 2.5 = 7.5cm
Work done = mgh = 7.5 mg
So ratio of work done = work done by worm A/ Work done by B = 5/7.5 = 2/3 = 2:3


Regards

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