Pls explain the reason also
Q.60. Arrange the following bonds in the order of increasing ionic character : C H, F H, Br H, Na I, K F and Li Cl.

Dear student

Firstly compare all the bonds of the compounds on the basis of the electronegativity differences. C-H bond will be least ionic as there is very little difference in the electronegativity between C and H. Now, out of Br-H and F-H, Br-H will be more polar as it will have a higher dipole moment. Where as although the difference in electronegativity between H-F is more but F can not easily accept an electron due to inter electronic repulsions so the bond also will be less polar or ionic. However the electronegativity difference between K-F is maximum as K is an alkali metal so will be maximum electropositive and thus will be the ionic character of the bond. Also Na-I will be more polar or more ionic than Li-Cl since Li is a small cation and thus will polarise the anion easily. 

Therefore, the increasing order of ionic character will be:

C-H < F-H < Br-H < Li-Cl < Na-I < K-F

Hope this information clears your doubts about the topic.

Looking forward to hear from again!!

Regards

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