Pls help:

2. Evaluate the following .
i   log   10 + 10 3                                                           ii   2 + 1 2   log   10 - 3 iii   2   log 5   +   log   8   - 1 2   log 4 iv   2   log   10 3 +   3   log   10 - 2 - 1 3   log   5 - 3 + 1 2   log   4

 

Dear student,

ii) 2+12log10-3using logmn=nlogm=2+-32log10=2+-32×1          --[as value of log 10=1]=2-32=4-32=12(iv) 2log103+3log10-2-13log5-3+12log4=2log103+3log10-2-13log5-3+12log22using logmn=nlogm=2×3log10+3×-2log10-13×-3log5+12×2log2=6log10-6log10+log5+log2=6log10-6log10+log5×2     --[using logm+logn=log(m×n)]=6log10-6log10+log10As value of log 10=1=6-6+1=1
Regards

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