Pls provide some other easier explanation to this question...pls Share with your friends Share 0 Sejal Gupta answered this Dear Student, the potential difference remain the same .because when you put the charge of -3Q on the surface the outer surface already had the charge of Q due to induction .so the net charge on the outer surface is -2Q and the inner surface have the same charge -Q.so the charge remain same in the inner surface and the the shell is conduting hence the PD remain the same .option 1 is correct .Regards 0 View Full Answer
