Pls sir I have problem ??

Dear Student,
Answer :

We draw line OA and OB .



In $∆$OPA and $∆$ OPB

OA = OB                         ( Radius of circle )
OP  = OP                         ( Common side )
AP = PB                           ( Given )

$\therefore$$∆$OPA $\cong$$∆$ OPB        ( By SSS  rule )
So,
$\angle$ OPA  = $\angle$ OPB            ------------- ( 1 )
And
we know
$\angle$ OPA  + $\angle$ OPB  =   180$°$      ( angle on same straight line )
So,
$\angle$ OPA  = $\angle$ OPB   = 90​$°$         ( By equation 1 )
Hence
OP perpendicular to AB                ( Hence proved prove)
Regards.