Pls solve for me Pls solve for me C / • des . ans - 742 sea Share with your friends Share 0 Sushant Ranjan answered this Dear Student, (i) : 1 mole of Na contains = 6.023*1023 atoms of Naor, 1.5 moles of Na contains = (6.023*1023 * 1.5) atoms of Na =9.0345*1023 atoms of Na(ii) :6.023*1023 ions of Ca2+ contains = 1 mole of Ca2+1 ion of Ca2+ contains = 16.023*1023 moles of Ca2+3.94*1024 ions of Ca2+ contains = 3.94*10246.023*1023 moles of Ca2+ = 6.54 moles of Ca2+(iii) :Molecular Mass of KMnO4 = 1*Mass of 'K' + 1*Mass of 'Mn' + 4*Mass of 'O' = 1*39 + 1*55 + 4*16 = 39+55+64 = 158gNow,1 mole of KMnO4 = 6.023*1023 molecules of KMnO4 = 158gTherefore,158g of KMno4 = 6.023*1023 molecules of KMnO4 1g of KMnO4 = 6.023*1023158 molecules of KMnO4 4.74g of KMnO4 = 6.023*1023 * 4.74158 molecules of KMnO4 = 1.807*1022 molecules of KMnO4 Regards 2 View Full Answer
