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Q. In the given figure, O is the centre of the circle, the radius of the circle is 3.1 cm and PA is a tangent drawn to the circle from point P. If OP = x cm and AP = 6.2 cm then find the value of x.

Dear Student,

In AOP,AO  AP        Tangent to a circle is perpendicular to the radius at the point of contact AOP is a right-angled triangle with OAP = 90°.Using Pythagoras' Theorem,AO2 + AP2 = OP2 3.12 + 6.22 = OP2 48.05 = OP2 OP = 48.05 cm = 6.93 cm approx.

​Hope this information will clear your doubts about this topic.

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  • 1
op = sqr root (6.2^2 + 3.1^2)
     = sqr toot ( 38.44+9.61)
     = sqr root (48.05)
     = 6.931
     = 6.93 cm (approx)



 
  • 3
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