Let the third number = xNow, first number = x - 30% of x = x - 30x100 = 70x100 = 7x10Now, second number = x - 40% of x = x - 40x100 = 60x100 = 6x10Let y% of 7x10 = 6x10⇒y100 × 7x10 = 6x10⇒7xy1000 = 6x10⇒7y = 600⇒y = 6007So, second number is 6007% of first number

Pls solve it

Let the third number = x Now, first number = x - 30 % of x = x - \frac{30 x}{100} = \frac{70 x}{100} = \frac{7 x}{10} Now, second number = x - 40 % of x = x - \frac{40 x}{100} = \frac{60 x}{100} = \frac{6 x}{10} Let y % of (\frac{7 x}{10}) = \frac{6 x}{10} \Rightarrow \frac{y}{100} \times \frac{7 x}{10} = \frac{6 x}{10} \Rightarrow \frac{7 xy}{1000} = \frac{6 x}{10} \Rightarrow 7 y = 600 \Rightarrow y = \frac{600}{7} So, second number is (\frac{600}{7}) % of first number .

-1

View Full Answer