Pls solve Q7 ii

Pls solve Q7 ii 3x+4y 3x — 2 y 7. Solve : (i) x + y = 2xy (ii) x + y = 7xy 2x — 3y = —xy (i) Dividing both the sides of each ec by xy, we get :

Dear Student,The given equations are x+y=7xy....(i)2x-3y=-xy....(ii)Dividing(i) and (ii) by xy, we get,1y+1x=7..(iii)  and 2y-3x=-1...(iv)LEt 1x=u, 1y=vSo, v+u=7    ]×3......(v)2v-3u=-1........(vi)it becomes,3v+3u=212v-3u=-1adding these two equations, we get,5v=20v=4put in (v), we get,4+u=7u=7-4u=3now, 1x=u=3x=13and1y=v=4y=14Regards!

  • 0
What are you looking for?