pls.solve QUESTION NO 22
Q. PQRST is a regulaer pentagon. Find the values of x, y and z.

Dear Student,

Please find below the solution to the asked query:

Given :  PQRST is a regular pentagon and we know in regular pentagon all five sides are equal to each other and all five interior angles is at 108°. So

PQR  =  QRS  =  RST =  STP = TPQ =  108°                             --- ( 1 )

In PQR , PQ =  QR , SIdes of regular pentagon PQRST , SO from base angle theorem we get :
QPR  =  QRP                          --- ( 2 )

And from angle sum property of triangle we get in PQR :

QPR  +  QRP  +  PQR  =  180° , Substitute values from equation 1 and 2 and get :

QPR +  QPR + 108° = 180° ,

2 QPR = 72° ,

2 x = 72°                                   , From given diagram

x  =  36°

And in RST , RS=  ST , Sides of regular pentagon PQRST , So from base angle theorem we get :
STR  =  SRT                          --- ( 3 )

And from angle sum property of triangle we get in RST :

STR  +  STR  +  RST =  180° , Substitute values from equation 1 and 3  and get :

STR +  STR + 108° = 180° ,

2 STR = 72° ,

STR = 36° , Then from equation 3 we get 

STR  =  SRT = 36°                              --- ( 4 )

And

RTP + STR =  RTP , Now we substitute values from equation 1 and 4 and get :

RTP + 36° =  108° ,

RTP  = 72° ,

z  =  72° , From given diagram

And

TRP + SRT +  QRP =  QRS , Now we substitute values from equation 1 and 4 and get :

TRP + 36° QRP=  108° ,

TRP  +  QRP= 72° ,

TRP +  36° = 72°                   (  As in triangle PQR x  = QRP  = 36° )

TRP = 36°

y  =  36° , From given diagram


Therefore,

x  = 36°  , y  = 36° and z  = 72°                                       ( Ans )

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Regards

  • -2
Hi sanskriti pz wait yar
  • -1
Wht do u want the value of x y z with steps or without
  • -1
with working and steps
  • 1
divide it into square and equilateral triangle
we have,
z + y = x + 90 ( exterior angle property of triangle ptr)
we also have 
y = x (alternative interior angle of pq parallel to tr)
so,
z=90
now,
x + prq = 180 (co interior angles) -1
and z + y + prq = 180 ( co interior angle ) -2
from 1 and 2

x + y + z+ 2prq = 180+180
we have x = y 
so,
2x+ 90 + 2prq=360
x+ prq =270/2
x+prq= 135
prq = 90-y
​x+ 90-y = 135
x= 45
 
  • -3
Please find this answer

  • 0
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