Pls. Solve this question in easy way of triangles

AP=BP [GIVEN]
AQ=QB [GIVEN]
AB=AB [COMMON]
BY S.S.S CRITERION OF CONGRUENCY WE CAN SAY THAT  TRIANGLE  APB=AQB

BY CPCT <PAB=<BAQ & <PBA=<ABQ

SO WE CAN SAY THAT
  • <PAB+<BAQ=<PAQ
  • <PAB+<PAB=<PAQ [PROVED ABOVE THAT <PAB=<BAQ. SO WE CAN WRITE <PAB INSTEAD OF <BAQ AS BOTH ARE EQUAL.]
  • <PBA+<ABQ=<PBQ[PROVED ABOVE THAT <PBA=<ABQ. SO WE CAN WRITE <PBA INSTEAD OF <ABQ AS BOTH ARE EQUAL.]
  • SO THIS PROVES THAT AB IS THE BISECTOR OF THE GIVEN ANGLES WHICH YOU ASKED..
... HENCE PROVED....

PLEASE LET ME KNOW THAT U UNDERSTOOD OR NOT....
IF U UNDERSTOOD, THEN PLS DONT FORGET TO LIKE MY ANSWER AND FOLLOW ME........

REGARDS..
BY-
​​​​​​​TANISH


                                         
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