Pls solve this question...

Dear student,
Self inductance =μ0n2AL=μ0n2L×2πr(r+h)n= Total number of turns /length L= Length of inductor r=radius ofcylinder cross section h=height of cylinder cross-section So, when all linear dimensions are increased by a factor of 2. Means r, h and L are made twice of originalThe new self inductance becomes I'=8I.

Regards

  • 0
What are you looking for?