Pls solve this question... Share with your friends Share 0 Anshu Agrawal answered this Dear student, Self inductance =μ0n2AL=μ0n2L×2πr(r+h)n= Total number of turns /length L= Length of inductor r=radius ofcylinder cross section h=height of cylinder cross-section So, when all linear dimensions are increased by a factor of 2. Means r, h and L are made twice of originalThe new self inductance becomes I'=8I. Regards 0 View Full Answer