Plz ans this question

Dear Student,
 

Marks	c.f.	Frequency
0 - 15 15 - 30 30 - 45 45 - 60 60 - 75 75 - 90	18 35 = cf 62 81 95 100	18 17 27 = f 19 14 5
		N=100

N = 100
N/2 = 100/2 = 50
Therefore, median class = (30 - 45)

Median = $L + \frac{({\displaystyle \frac{N}{2}} - cf)}{f} x h$
where,
l = lower limit of median class interval
cf = cumulative frequency preceding to the median class frequency
f = frequency of the class interval to which median belongs
h = width of the class interval
N = Sum of all frequencies.

Median = $30 + \frac{(50-35)}{27} x 15$ = 30 + 8.33
Median = 38.33

Regards