PLZ ANS WITH STEPS AND FORMULAS
Calculate the number of gram atoms and atoms present in 80 g of sulphur.
( a )   2 . 5 ,   15 . 05 × 10 23 ( b )   3 . 5 ,   16 . 05 × 10 23 ( c )   0 . 5 ,   13 . 3 × 10 22 ( d )   2 . 3 ,   15 . 05 × 10 23

The solution is as follows:

For 1 mole of S, gram-atoms of S is 1.

Thus,

     Gram atoms in 80 g sulphur = number of moles in 80 g S
                        = Given massMolar mass=8032 =2.5Number of atoms of S in 80 g = no of moles×NA                            = 2.5×6.023×1023                             = 15.05×1023

The correct option is (a).

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Ans. Should be option- (A) Gram atoms = n= no. of moles n = given mass ÷ molecular mass Given mass = 80 Molecular mass of sulphur = 32 gram n = 80g ÷ 32g n = 2.5 gram atoms 😀😁😍😘😙 😶n = N÷Na😚 here n= no. Of moles N = given molecules Na= avogadro's no. n=2.5 N=? Na= 6.022 × 10^23 N = n×Na N= 2.5 × 6.022 × 10^23 N = 15.055 × 10^23 😘👍
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