Plz answer them all
Plz answer them all VIKASH EDUCATIONAL INSTITUTIONS
VIKASH RESIDENTIAL SCHOOL, BARGARH
Summer Holiriay Assignment — 2018-19
CLASS - X
GLISH:
the nr,vel diary ofa Young Girr as preserihc•dby CBSIZ Write sketch ofthe
chNacters in literature notebook. 1 00 words
• Otto prank
areol
MrsV'u1 Dann
• Edith Frank
• Peter Van
• Anne Frank
Daan
You ate Rekha "ving a: 3 dS3 Raghupura, New Oathö Sot •e women have been robbed of the."r • chaw,"
earnntv. in the of your block dunng rush hour. Oy young boys racing bike You are very much womed
about such 'ncidents, Write a letter to the Editor or a local newspaper to draw attention of the authonty concerned
about it,
(3) •snug
( Q) rrA
MATHEMATICS:
OZFind the greatest number of 6 digits exactlv divisible by 24,15 and 36.
y. prove that is irrational.
08 the HCF or 78 and143 is expressible in the form 78m —143?then find the value of m.
U"6n GT Road, three consecutive traffic lights change after24, 36 and 42 sec. It the lights are first switched on at
6_00 am, then at what time will thev change simultaneous's?
n a seminer, the number of participants in Hindi, English and Mathematics are 45.63and81 respectively. Find
the minimum number of rooms required in each room the same numbers of participants are to be seated
and all of them being in the same subject-
—rove Ihar the square of any positive integers of the forre or Sqw4 for some integer q.
O:l€a and are the zeros of the quadratic polynomiai x2—4X+3, find the value Of
all the zeros of the polynomial 14x'-19x-6, if two of its zeros are -2 and -i.
s9
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1. 999720
2. Let √2 + √3 = (a/b) is a rational no.
On squaring both sides , we get
2 + 3 + 2√6 = (a2/b2)
So,5 + 2√6 = (a2/b2) a rational no.
So, 2√6 = (a2/b2) – 5
Since, 2√6 is an irrational no. and (a2/b2) – 5 is a rational no.
So, my contradiction is wrong.
So, (√2 + √3) is an irrational no.
3. hcf of 78 and 143 is 13
therefore m=2
4. 6:08:24 am
5. nine students
6. Let x be any positive integer
Then x = 5q or x = 5q+1 or x = 5q+4 for integer x.
If x = 5q, x2 = (5q)2 = 25q2 = 5(5q2) = 5n (where n = 5q2 )
If x = 5q+1, x2 = (5q+1)2 = 25q2+10q+1 = 5(5q2+2q)+1 = 5n+1 (where n = 5q2+2q )
If x = 5q+4, x2 = (5q+4)2 = 25q2+40q+16 = 5(5q2 + 8q + 3)+ 1 = 5n+1 (where n = 5q2+8q+3 )
∴in each of three cases x2 is either of the form 5q or 5q+1 or 5q+4 and for integer q.
7. x2-4x+3=0
x2-3x-x+3=0
x(x-3)-1(x-3)=0
(x-3)(x-1)=0
x=1,3
alpha=1 and beta=3
a4b3+a3b4
= 14 X 33 + 13 X 34
= 1 X 27 + 1 X 81
= 27 + 81
= 108
2. Let √2 + √3 = (a/b) is a rational no.
On squaring both sides , we get
2 + 3 + 2√6 = (a2/b2)
So,5 + 2√6 = (a2/b2) a rational no.
So, 2√6 = (a2/b2) – 5
Since, 2√6 is an irrational no. and (a2/b2) – 5 is a rational no.
So, my contradiction is wrong.
So, (√2 + √3) is an irrational no.
3. hcf of 78 and 143 is 13
therefore m=2
4. 6:08:24 am
5. nine students
6. Let x be any positive integer
Then x = 5q or x = 5q+1 or x = 5q+4 for integer x.
If x = 5q, x2 = (5q)2 = 25q2 = 5(5q2) = 5n (where n = 5q2 )
If x = 5q+1, x2 = (5q+1)2 = 25q2+10q+1 = 5(5q2+2q)+1 = 5n+1 (where n = 5q2+2q )
If x = 5q+4, x2 = (5q+4)2 = 25q2+40q+16 = 5(5q2 + 8q + 3)+ 1 = 5n+1 (where n = 5q2+8q+3 )
∴in each of three cases x2 is either of the form 5q or 5q+1 or 5q+4 and for integer q.
7. x2-4x+3=0
x2-3x-x+3=0
x(x-3)-1(x-3)=0
(x-3)(x-1)=0
x=1,3
alpha=1 and beta=3
a4b3+a3b4
= 14 X 33 + 13 X 34
= 1 X 27 + 1 X 81
= 27 + 81
= 108
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