Dear student,P1≡(0,0)P2≡(-2,9)Slope of perpendicular(m)= 9-0-2-0=-92Therefore, slope of line= -1m=-1-92=29Eqn of line:y-9x+2=29⇒9y-81=2x+4⇒9y-2x-85=0Regards

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D e a r s t u d e n t, P 1 \equiv (0, 0) P 2 \equiv (- 2, 9) S l o p e o f p e r p e n d i c u l a r (m) = \frac{9 - 0}{- 2 - 0} = \frac{- 9}{2} T h e r e f o r e, s l o p e o f l i n e = - \frac{1}{m} = - \frac{1}{(\frac{- 9}{2})} = \frac{2}{9} E q n . o f l i n e : \frac{y - 9}{x + 2} = \frac{2}{9} \Rightarrow 9 y - 81 = 2 x + 4 \Rightarrow 9 y - 2 x - 85 = 0 R e g a r d s

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