Plz explain?? Share with your friends Share 0 Lovina Kansal answered this Dear student We have,r1r2cosθ1+isinθ1cosθ2+isinθ2=r1r2cosθ1 cosθ2+icosθ1sinθ2+isinθ1cosθ2+i2sinθ1sinθ2=r1r2cosθ1 cosθ2+i2sinθ1sinθ2+icosθ1sinθ2+isinθ1cosθ2 ∵i2=-1=r1r2cosθ1 cosθ2-sinθ1 sinθ2+isinθ1cosθ2+cosθ1sinθ2=r1r2 0 View Full Answer