Plz hlp! Why does a galvanometer show momentary deflection at the time of charging or discharging a capacitor? Write the necessary expression to explain this observation?(this board ques is little indirect can u tell me to which chapt it belong to)

Dear Student
the momentary deflection is due to set up of displacement current in the circuit  which is mentioned below
Idisplacement  =ε0dφdt(here φ is electrical flux)Regards

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There is a momentary deflection at the time of charging or discharging because of the displacement current formed.
This concept is related to the chapter EM Waves.
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Momentary deflection is due to displacement current which changes magnetic flux and hence inducing an emf..
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During charging and discharging of the capacitor, there is a flow of charge from the battery towards the plates of the capacitor, which produces a conduction current in the circuit. Hence, the galvanometer present in the circuit shows momentary deflection.

As the charge on the capacitor grows, the conduction current in the wires increases. When the capacitor is fully charged, the conduction current stops flowing in the wires. During charging or discharging of the capacitor, there is no conduction current between the plates of capacitor, as they are not connected by any conduction material. Therefore, in this region, a current must exist that makes the total current in the circuit continuous. This observation leads to modifying the Ampere's circuital law. 

Thus, there must be displacement current along with the conduction current in the circuit having the property of continuity, although individually they may not be continuous.


Maxwell modified Ampere's circuital law in order to make it logically consistent. He stated Ampere's circuital law in the form,
∮B⇀ . dl⇀ = μ0(I + ID) = μ0(I + ∈0dϕEdt)
, where dϕEdt is rate of change of electric flux between the plates of the capacitor.

This is the generalised expression of Ampere's law.

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