Plz solve question no 13
Dear student,
Let x, y unit of goods A and B are produced respectively.
Let Z be total revenue
Here Z = 100x + 120y ....(i)
Also
2x + 3y ≤ 30 ....(ii)
3x + y ≤ 17 ....(iii)
x ≥ 0 ....(iv)
y ≥ 0 ....(v)
On plotting graph of above constants or inequalities (ii), (iii), (iv) and (v). We get shaded region as feasible region having corner points A, O, B and C.
For co-ordinate of 'C'
Two equations (ii) and (iii) are solved and we get coordinate of C = (3, 8)
Now the value of Z is evaluated at corner point as:
Therefore maximum revenue is Rs. 1,260 when 2 workers and 8 units capital are used for production.
Let x, y unit of goods A and B are produced respectively.
Let Z be total revenue
Here Z = 100x + 120y ....(i)
Also
2x + 3y ≤ 30 ....(ii)
3x + y ≤ 17 ....(iii)
x ≥ 0 ....(iv)
y ≥ 0 ....(v)
On plotting graph of above constants or inequalities (ii), (iii), (iv) and (v). We get shaded region as feasible region having corner points A, O, B and C.
For co-ordinate of 'C'
Two equations (ii) and (iii) are solved and we get coordinate of C = (3, 8)
Now the value of Z is evaluated at corner point as:
| Corner Points | Z= 100x+120y |
| (0,10) | 1200 |
| (0,0) | 0 |
| (17/3 ,0) | 1700/3 |
| (3,8) | 1260 (Maximum) |
Therefore maximum revenue is Rs. 1,260 when 2 workers and 8 units capital are used for production.