Plz solve the que no 6
Q.6. In the given figure, O is the centre of the circle passing through the  points A, B, C and D and DC is produced to point E. If BAD = 60 ° , find BCE and BOD.

Dear student,
Here is the solution of your asked query:
We know that angle subtended at the center of circle is double the angle subtended at any point on circle.So we have;BOD=2BAD=2×60°=120°Also, ABCD is a cyclic quadrilateralSo, BAD+BCD=180°                                  {Sum of opposite angles of cyclic quadrilateral}60°+BCD=180°BCD=180°-60°=120°Then, BCE=180°-BCD = 180°-120°=60°
Regards

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