Plz solve this problem

Dear student,

Let PR be 'x' and QR be = 25-x

Using Pythagoras Theorem,

==>PR^2 = PQ^2 + QR^2

     x^2   = (5)^2 + (25-x)^2

     x^2   = 25 + 625 + x^2 - 50x

     50x   = 650

          x   = 13

therefore, PR = 13 cm

and,          QR = (25 - 13) = 12 cm

Now,  Sin P = opposite/hypotenuse = QR/PR = 12/13

          Tan P= opposite/adjacent      = QR/PQ = 12/5

          Cos P= adjacent/hypotenuse = PQ/PR = 5/13

Regards