# Plzz solve 3,4,5,6...URGENT Dear Student,

Solutions for the questions are as under:

In the given figure, we can see that;

Hence, considering

Thus, based on SAS (Side Angle Side) property we can say that  are congruent with each other.
Therefore, BC = DE  (the third side of the congruent triangles)

It is given in the question that  are congruent with each other. Thus, the corresponding sides which are equal with each other as per the properties of congruency, will be;

But $BC$ will not be equal to $QR$, as these are not the corresponding sides. Thus it is false to say that .

It is given in the question that  are congruent with each other. Thus, the corresponding sides which are equal with each other as per the properties of congruency, will be;

Hence, we can definitely say that $PR$ will be equal to $EF$, as these are the corresponding sides. Thus it is true to say that .

It is given in the question that angles A, B and C of the triangle are equal with each other. Hence we can also say that all the three angles are congruent with each other.

Thus,

Now, in a triangle, sides opposite to the equal and congruent angles are always equal with each other.

Hence,

Therefore, we can that .
Since, in $△ABC$, all the angles are equal and all the sides are equal, thus $△ABC$ is an equilateral triangle.

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(Ans.4) No, BC can't be said equal to QR because when the 2 given triangles are superimposed on each other then side BC doesn't overlap side QR instead it overlaps side QP. (Ans.5) Yes, PR=EF because when the 2 given triangles are superimposed on each other then PR overlaps EF. (Ans.6) As angle A = angle B = angle C so let them be x. As we know that angle sum property of any triangle is 180°. Therefore, x+x+x=180° I.e. x= 60°. As all the angles of the given triangle are equal hence it is an equilateral triangle.
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GIVEN; ANGLE BAD =30 AND ANGLE EAC =30
TO PROVE: BC=DE
PROOF:
ANGLE BAD = ANGLE EAC (GIVEN)
ANGLE BAD + ANGLE DAC = ANGLE EAC + ANGLE DAC
ANGLE BAC = ANGLE DAE
IN TRIANGLE BAC AND TRIANGLE DAE:
ANGLE BAC= ANGLE DAE(PROVED ABOVE)
AC=AE(GIVEN)
THEREFORE TRIANGLE BAD IS CONGRUENT TO TRIANGLE DAE (BY SAS)
SO BC=DE(BY CPCT)

THIS IS THE ANSWER FOR UR THIRD QUESTION
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