Plzzzz solveeee thisssss

Dear student,I assume that your question to factorise the given expressioni) a2-b2c2-d2-4abcd=a2c2-a2d2-b2c2+b2d2-4abcd=a2c2+b2d2-2abcd-a2d2-b2c2-2abcdUsing x2+y2-2xy=(x-y)2 and  x2+y2+2xy=(x+y)2=ac-bd2-a2d2+b2c2+2abcd=ac-bd2-(bc+ad)2 Using x2-y2=(x+y)(x-y)=ac-bd+bc+adac-bd-bc-ad=a(c+d)+b(c-d)(a(c-d)-b(a+d))ii)4x2-y2-3xy+2x-2y=x2+3x2-y2-3xy+2x-2y=x2-y2+3x2-3xy+2x-2yx2-y2=(x+y)(x-y)=(x+y)(x-y)+3xx-y+2x-y=x-yx+y+3x+2=x-y4x+y+2Regards

  • 0
What are you looking for?