point p(x,y)is equidistant from the point A(a-b,a+b) & B(-a-b,a+b),then prove that x-a=0
If a point P(x,y) is equidistant from two points A & B, then P lies on the perpendicular bisector of AB.
We see that y coordinates of A & B are the equal. So AB parallel to x axis. So perpendicular bisector is perpendicular to x axis.
It is given by: x = [(a-b) + (-a-b) ] /2
x = -b or x + b = 0
So kindly recheck the question it ,must be x+b = 0
We see that y coordinates of A & B are the equal. So AB parallel to x axis. So perpendicular bisector is perpendicular to x axis.
It is given by: x = [(a-b) + (-a-b) ] /2
x = -b or x + b = 0
So kindly recheck the question it ,must be x+b = 0