potential difference of 50V is maintained between the two plates of a parallel plate condenser separated by 5 mm of air find energy stored in unit volume of air between plates of condenser

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    Given Potential difference across capacitor=50V, distance between plates=5mm=5×10-3mEnergy in unit volume that is area×distance=1A×d=1so A=1dCapacitance,C=ε0Ad=ε0d2=8.8×10-12(5×10-3)2=0.325×104Farad(ε0=8.8×10-12Fm-1)Energy=12CV2=12×0.325×50×50=440JHope this information will clear your doubts about topic.                If you have any more doubts just ask here on the forum and our experts will try to help you out as soon aRegards

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