PQ and PT are tangents drwan from a point P to a circle with centre O such that angle QPT=120 then angle QOT is equal to??

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angle QPT=120angle PQO=90 (radius is always perpendicular to the tangent at the point of contact)angle PTO=90 ( --same as above-)therefore angle QOT = 360 - ( 120 + 90+90) ( bcuz sum of all angles of a quadrilateral is equal to 360 and PQOT is a quadrilateral)therefore, angle QOT = 360-300 = 60

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