pqrs is a quadrilateral and o is a point inside it (other than the point of intersection of the diagonals),prove that( op+oq+or+os)​ greater than(pr+qs)

Hi, 
we know that in a triangle sum of two sides is greater than third so 


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Now if we will join diagonals then in triangle PQR, QRS, RSP and PSQsum of two side is greater than third so PQ+QR>PRQR+RS>SQSR+PS>RPPS+PQ>SQadd all 2PQ+QR+RS+SP>2PR+SQPQ+QR+RS+SP>PR+SQputting this in above we get 2OP+OQ+OR+OS>PR+SQcorrect relation is this 


 

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