Prove that 1 1+p 1+p+q

2 3+2p 1+3p+2q = 1

3 6+3p 1+6p+3q

11+p1+p+q23+2p1+3p+2q36+3p1+6p+3q=11+p1+p23+2p1+3p36+3p1+6p+11+pq23+2p2q36+3p3q By determinant Property=11+p1+p23+2p1+3p36+3p1+6p+q11+p123+2p236+3p3=11+p1+p23+2p1+3p36+3p1+6p+q(0) by determinant property=11+p1+p23+2p1+3p36+3p1+6p=11+p123+2p136+3p1+11+pp23+2p3p36+3p6p=111231361+1p122p133p1+11p233p366p+1pp22p3p33p6p=111231361+p111221331+p111233366+p11p223p336p=111231361+p(0)+p(0)+p(0)=111231361=1(3×1-6×1)-1(2×1-3×1)+1(2×6-3×3)=1(3-6)-1(2-3)+1(12-9)=-3+1+3=1     Proved

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