prove that |1+a 1 1| |1 1+b 1| |1 1 1+c| = ab+bc+ca+abc

To Prove:-1+a1111+b1111+c=ab+bc+ca+abcLHS1+a1111+b1111+cApplying C1C1-C2 and C2C2-C3a01-bb10-c1+cApplying C1C1-aC3001-b-ab1-a-ac-c1+cExpanding along R1, we get0-0+1-c-b-a-b-a-ac=cb+ca+ab+abc=ab+bc+ca+abc=RHSHence Proved.

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