Prove that 1/log(base 2) n + 1/log(base 3) n+...+1/log(base 50) n=1/log (base50!)n

Dear Student,

1log2n+ 1log3n + 1log4n +......+ 1log50n= logn2 +logn3 + logn4 + .....+ logn50  .....as logab = 1logba= logn2×3×4×......×50  ......as logba +logbc = logbac= logn50! .......here 50! means 50 factorial= 1log50!n .....as logab = 1logbaHence proved

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