prove that if a body is thrown vertically upward , the time of ascent is equal to the time of descent.
Time of ascent be t seconds and the object be thrown with an initial velocity be u m/s.
Time of descent be t' seconds and the object final velocity be v m/s. The distance covered will be the same as when the object is thrown upwards.
From equation (1) and (2) we can see that u = v.
t' = t, that is, time of ascent is equal to time of descent.
g=9.8 , t1=time taken for ascent , u=initial velocity , v=final velocity=0
t1= (v-u)/-g= (0-u)/g = u/g
g=9.8 , u=initial velocity=0 , v=final velocity, t2=time taken for the descent
t2= (v-u)/g= (v-o)/g= v/g
The velocity with which the body is thrown = The velocity with which the body hits the ground. (experimented truth)
or, the time of ascent = the time of descent (PROVED)