prove that :

sec(70-A) = cosec(20+A)

sec70-A=sec90-20-A=sec90-20+A=cosec20+AAs we know that sec90-x=cosecx

  • 8
sec(70-A)
=sec(90-(70-A))      (since, sec(90-theta)=cosec theta)
=cosec(20+A)
  • 4
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