Prove that: sin2A.tanA + cos2A.cotA + 2sinA.cosA = tanA+cotA Share with your friends Share 8 Anuradha Sharma answered this sin2AtanA+cos2AcotA+2sinAcosA= 1-cos2AtanA+1-sin2AcotA+2sinAcosA=tanA+cotA-cos2AtanA-sin2AcotA+2sinAcosA=tanA+cotA-cos2A×sinAcosA-sin2AcosAsinA+2sinAcosA=tanA+cotA-sinAcosA-sinAcosA+2sinAcosA=tanA+cotA 6 View Full Answer