Prove that tan[(inverse) x ] + cot[(inverse) x ] = pi/2.

Dear Student,

L.H.S.=tan-1x+cot-1x            =tan-1x++tan-11x            =tan-1x+1x1-x1x            =tan-1x+1x0            =tan-1            =tan-1tanπ2            =π2            =R.H.S.Hence Proved.

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