Prove that:
  • ​The difference between a three-digit number and the number formed by reversing the digits is always a multiple of 99

Dear Student,

Suppose the three digit number is ABC, i.e. 100A+10B+C          .....iNow, reversing the digit CBA i.e., 100C+10B+A                            .....iiSubtracting ii from i100a+10B+c-100C+10B+A99A-99C99A-cTherefore the difference is always a multiple of 99.Hence Proved

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