Prove that: The difference between a three-digit number and the number formed by reversing the digits is always a multiple of 99 Share with your friends Share 1 Ankita Agarwal answered this Dear Student, Suppose the three digit number is ABC, i.e. 100A+10B+C .....iNow, reversing the digit CBA i.e., 100C+10B+A .....iiSubtracting ii from i100a+10B+c-100C+10B+A99A-99C99A-cTherefore the difference is always a multiple of 99.Hence Proved Regards 2 View Full Answer