Prove that this function is onto Q 7 f : [- 3π, 2π] →[- 1, 1] defined by - Maths - Relations and Functions

Question

Prove that this function is onto
Q 7 f : [- 3 π , 2 π ] → [- 1, 1] defined by f (x)
= sin 3x

Aarushi Mishra · Accepted Answer

f:-3π, 2π→-1,1fx=sin 3xf-π6=sin -π2=-1fπ6=sin π2=1Since fx is continuous therefore, it will take all values between -1 and 1 in the interval -π6, π6 itselfHence fx is onto

Prove that this function is onto. Q.7. f : [- 3 π , 2 π ] → [- 1, 1] defined by f (x) = sin 3x.

Prove that this function is onto.
Q.7. f : [- 3 $π$ , 2 $π$ ] $\to$ [- 1, 1] defined by f (x) = sin 3x.