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Prove that triangle AOC is congruent to triangle BOD

$\mathbf{2}\mathbf{.}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathit{P}\mathit{r}\mathit{o}\mathit{v}\mathit{e}\mathbf{}\mathit{t}\mathit{h}\mathit{a}\mathit{t}\mathbf{}\mathbf{\u25b3}\mathit{A}\mathit{O}\mathit{C}\mathbf{}\mathbf{\cong}\mathbf{}\mathbf{\u25b3}\mathit{B}\mathit{O}\mathit{D}\mathbf{.}\mathbf{}$

Hi Friend,

Here is the solution to your query-

**SOLUTION**ANGLE ACO= ANGLE BDO (65)

*[ALTERNATE ANGLES]*CO=OD(5 CM)

ANGLE AOC =ANGLE BOD (35)

**[VERTICALLY OPPOSITE ANGLES]**Thus TRIANGLE AOC is

**TRIANGLE BOD.**

__congruent to__Proved by

**rule.**

__ASA__Hope this answer has satisfied your doubt.

Thanks and Regards,

Shambhavi Jha

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