Prove that triangle AOC is congruent to triangle BOD

$\mathbf{2}\mathbf{.}\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathit{P}\mathit{r}\mathit{o}\mathit{v}\mathit{e}\mathbf{ }\mathit{t}\mathit{h}\mathit{a}\mathit{t}\mathbf{ }\mathbf{△}\mathit{A}\mathit{O}\mathit{C}\mathbf{ }\mathbf{\cong }\mathbf{ }\mathbf{△}\mathit{B}\mathit{O}\mathit{D}\mathbf{.}\mathbf{ }$

 

​Hi Friend,
Here is the solution to your query-

SOLUTION

ANGLE  ACO= ANGLE BDO (65) [ALTERNATE ANGLES]
​CO=OD(5 CM)
ANGLE AOC =ANGLE BOD (35) [VERTICALLY OPPOSITE ANGLES]


​Thus TRIANGLE AOC is congruent to TRIANGLE BOD.
​Proved by ASA rule.

​Hope this answer has satisfied your doubt.
Thanks and Regards,
Shambhavi Jha

​