prove tht the points r collinear using section formula the points r A(2,2) B(4,0) C(-6,10) - Maths - Coordinate Geometry

Question

prove tht the points r collinear using section formula??? the
points r A(2,2) B(4,0) C(-6,10) hw should we do tis sum????

Aakash Sharma · Accepted Answer

Hi! Here is the answer to your query Distance between two points = $\sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}$ Distance between $AB = \sqrt{(4 - 2)^{2} + (0 - 2)^{2}}$ $= \sqrt{4 + 4} = \sqrt{8} = 2 \sqrt{2} ----- (1)$ Distance between $BC = \sqrt{(- 6 - 4)^{2} + (10 - 0)^{2}}$ $= \sqrt{100 + 100} = \sqrt{200} = 10 \sqrt{2} ----- (2)$ Distance between $AC = \sqrt{(- 6 - 2)^{2} + (10 - 2)^{2}}$ $= \sqrt{64 + 64} = \sqrt{128} = 8 \sqrt{2} ----- (3)$ If we analyze result (1), (2) and (3), we find BC = AB + AC According to definition of collinear, a set of points are said to be collinear if they lie in a straight line Hence, the points A(2, 2), B(4, 0) and C(–6, 10) are collinear Cheers!

prove tht the points r collinear using section formula??? the points r A(2,2) B(4,0) C(-6,10)......hw should we do tis sum????