Q 20 20 Solve : 1 + x2 + y2 + x2y2 dx + xydy = 01 - Maths - Differential Equations

Question

Q 20

20   Solve   :   1   +   x 2   +
  y 2   +   x 2 y 2   dx   +   xydy
  =   0 1   +   y 2   =   - 1  
+   x 2   -   log   1   +   x 2 x
  -   1 x   +   C

Neha Sethi · Accepted Answer

Kindly refer the similar link for your
query

https://www meritnation
com/ask-answer/question/1-x2-y2-x2y2-1-2-xy-dy-dx-0-how-to-solve-dis-diffrential-equ/differential-equations/4259729
Regards

Q.20 20 . Solve : 1 + x 2 + y 2 + x 2 y 2 dx + xydy = 0 1 + y 2 = - 1 + x 2 - log 1 + x 2 x - 1 x + C

Q.20

$20 . Solve : \sqrt{1 + x^{2} + y^{2} + x^{2} y^{2}} dx + xydy = 0 [\sqrt{1 + y^{2}} = - \sqrt{1 + x^{2} - \log |\frac{\sqrt{1 + x^{2}}}{x} - \frac{1}{x}|} + C]$