Q.35. The value of 0 T / 2 sin 2 πt T d t  is equal to
(1) Zero
(2) T π
(3) 2 T π
(4) 2 π

Dear Student,

Let,I=0T2sin2πtTdtI=-T2πcos2πtTT20I=-T2πcos2π×T2T-cos2π×0TI=-T2πcosπ-cos0I=-T2π-1-1I=-T2π×-2=Tπ So, option 2 is correct.

Regards.

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