Q 80 For 10 min each, at 27 C, from two identical holes nitrogen and an unknown gas are - Chemistry -

Question

Q 80 For 10 min each, at 27 ° C , from two identical holes
nitrogen and an unknown gas are leaked into a common vessel of 31
capacity The resulting pressure is 4 18 bar and the mixture
contains 0 4 mole of nitrogen The molar mass of the unknown gas
is
(a) 112 g   m o l - 1
(b) 242 g   m o l - 1
(c) 224 g   m o l - 1
(D) 422 g   m o l - 1

Yasodharan · Accepted Answer

Dear Student,

The computation are as expressed below,

n=PVRT=4 18×30 0821×300=0
5 molegiven moles of nitrogen = 0
4so moles of unknown gas = 0 5-0 4=0
1 moleby using grahm's law of diffusion we get,rN=no
of molestime taken=0 410=0 04 molminrunknown=0 110=0
01 molminwe know, rNrunknown =munknownmN0 040
01=munknown14 007munknown =224
112 gmolHence answer is Option (C) 224 gmol

Regards