Q. A metallic rods completes its circuit as shown in the figure. The circuit is normal to a magnetic field of B = 0.15 T. If the resistance of the circuit is 3 ohm the force required to move the rod with a constant velocity of 2m/sec. is: 
(1) 3.75 X  10 - 3  N 
(2) 3.75 x 10 2
(3) 3.75 x 10 - 2
(4) 3.75 x  10 - 4  N

Dear student,



let us consider coil PQRS as shown above.Area of coil=lx=Sflux =Blx=ϕdϕdt=d(Blx)dt=Blvenduced emf, e=-dϕdt=Blv(as x is decreasing)current in the loop is given by,I=εR=BlvRForec required is given by,F=BILF=B2l2vR=0.15×0.15×0.5×0.5×23=3.75×10-3NRegards

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