Q= A search coil of 1000 turns,,resistance 5 ohm and cross section of 5 cm2 is connectes - Physics - Electromagnetic Induction

Question

Q= A search coil of 1000 turns,,resistance 5 ohm and cross section
of 5 cm2 is connectes in series with galvanometer of
resistance of 45 ohm,,,,The coil is placed between poles of an
electromagnet When the coil is withdrawn from the pole pieces in
1ms,,,,the charge flowing in galvanometer is 2mc,,,,,The magnetic
field of electromagnet is??

Ved Prakash Lakhera · Accepted Answer

The current  detected by the galvanometer when search is removed from the magnetic field of the pole pieces is given by,       I = B ANRC+G
I = qt=2×10-31×10-3=2A
A = 5×10-4m2 N = 1000 turns
RC+G = 5+45 = 50 ohm
Putting all these values in the formula of induced current we get,       2= B× 5×10-4×100050OR           B = 1005×1000×10-4=200 T