Q:differentiate - tan^-1 (2^[x+1] / 1 - 4^x) Share with your friends Share 4 Varun.Rawat answered this Let y = tan-12x+11 - 4x=tan-12.2x1 - 2x2Put 2x = tan θSo, y = tan-12 tan θ1 - tan2θso, y = tan-1tan 2θ⇒y = 2θ⇒y = 2 tan-12x⇒dydx = 2 × 1 1 +4x × 2x log 2⇒dydx = 2x+1 log 21 + 4x 32 View Full Answer
